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Fernanda la maria Exponential Loss

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As an aside, you might not want to use an exponential loss.

  • Now to your specific question: Your label values are 0 and 1.

  • Is there a simple way to implement my own exponential function.

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Anyway, I think of it as being: exp mismatch between prediction and actual , where exp mismatch is used to strongly amplify being wrong.

  • Although the first and last predictions are right, they are only mildly right, while the second prediction is strongly wrong, making the predictions overall more wrong than right.

  • Your known class labels are 0 and 1, where 1 indicates that the image is a picture of a bird, and 0 indicates that it is not a bird.




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